准备
手机：Google Nexus 5
工具：
- APK改之理（APK IDE）
- Package Capture by Grey Shirts
分析文件：东软智慧校园平台（华东交大版）
先来简单看一下这个应用
我们使用这个账号登陆
username:20142110070202
password:011211
打开Package Capture进行抓包
可以看到，登陆时，移动端向服务端发送一个get请求
portal.ecjtu.edu.cn/dcp/service?action=0B38EC05B0815AFB59A1B6171DD8378702E08185784ADC47B213462CC176EBC626865CAE40CF998812E25558152958267F28B8BE59532A45283F2A274FA363CB685347955B330164CDEFA8228F011F4BB73C36BFF072DB9C
服务器返回一段json数据
{"message":{"map":{"UNIT_NAME":"软件学院","USER_ID":"20142110070202","UUID":"201412019176","ID_TYPE":"1","UNIT_ID":"1021","USER_PASSWORD":"?h?g?g+t.[=dR);:","USER_ACCOUNT":"20142110070202","USER_SEX":"1","IS_ACTIVE":"1","BEGIN_TIME":"20141219","USER_FULLNAME":"史泰龙","USER_FIRST_LOGIN":"0","USER_DESCRIPTION":"史泰龙","USER_ACCOUNT_LOCKED":"1","IS_MAIN_IDENTITY":"1","END_TIME":"20600606"}},"success":true}
可见移动端与服务端之间的传输是加密的
用APK改之理打开这个app
smali不易阅读，所以点击上面的“打开Java源码”。
找到关键词 “/dcp/service?action=” 关键代码：
public final a a(String paramString1, String paramString2, String paramString3)
{
String str = paramString3;
if (paramString3 == null) {
str = "";
}
paramString1 = "method=checkUserLoginIFS&idNumber=" + paramString1 + "&UserPwd=" + paramString2 + "&logonIP=" + str;
try
{
paramString2 = com.neusoft.edu.v6.ydszxy.hdjiaoda.appcenter.c.b.a.a(paramString1);
paramString1 = paramString2;
}
catch (Exception paramString2)
{
for (;;)
{
paramString2.printStackTrace();
}
}
paramString1 = "/dcp/service?action=" + paramString1;
return (a)a(this.a.a(paramString1), new a());
}
通过源码得知，paramString1本来是
method=checkUserLoginIFS&idNumber=xxx&UserPwd=xxx&logonIP=xxx
这样的形式，但是通过
com.neusoft.edu.v6.ydszxy.hdjiaoda.appcenter.c.b.a.a
方法的加密，变成了上面的get请求action后面的密文，跟踪到appcenter.c.b.a.a，
关键代码：
public static String a(String paramString)
{
Object localObject = new DESedeKeySpec("neusofteducationplatform".getBytes());
localObject = SecretKeyFactory.getInstance("desede").generateSecret((KeySpec)localObject);
Cipher localCipher = Cipher.getInstance("desede/CBC/PKCS5Padding");
localCipher.init(1, (Key)localObject, new IvParameterSpec("01234567".getBytes()));
return a(localCipher.doFinal(paramString.getBytes("utf-8")));
}
private static String a(byte[] paramArrayOfByte)
{
String str1 = "";
int i = 0;
for (;;)
{
if (i >= paramArrayOfByte.length) {
return str1;
}
String str3 = Integer.toHexString(paramArrayOfByte[i] & 0xFF);
String str2 = str3;
if (str3.length() == 1) {
str2 = '0' + str3;
}
str1 = str1 + str2.toUpperCase();
i += 1;
}
}
通过分析，可以得知加密方式是DESede(TripleDES，对每个数据块应用三次DES加密算法)，算法模式为CBC(每个平文块先与前一个密文块进行异或后，再进行加密。)，填充算法为PKCS5Padding(The number of bytes to be padded equals to “8 - numberOfBytes(clearText) mod 8”. So 1 to 8 bytes will be padded to the clear text data depending on the length of the clear text data.)，初始化向量(IV,Initialization Vector)为"01234567",向量的作用其实就是salt。
private static String a的作用应该是把bytes转成大写的Hex字符串。
于是根据分析得到的加密思路写下解密算法
public static String desDecode(String encryptText, String pk)//encryptText为密文，pk为私钥，通过跟踪到的代码可知为"neusofteducationplatform"
throws Exception
{
java.security.Key deskey = null;
DESedeKeySpec spec = new DESedeKeySpec(pk.getBytes());
SecretKeyFactory keyfactory = SecretKeyFactory.getInstance("desede");
deskey = keyfactory.generateSecret(spec);
Cipher cipher = Cipher.getInstance("desede/CBC/PKCS5Padding");
IvParameterSpec ips = new IvParameterSpec("01234567".getBytes());
cipher.init(2, deskey, ips);
System.out.println(encryptText);
byte decryptData[] = cipher.doFinal(hexStringToBytes(encryptText));
return new String(decryptData, "utf-8");
}
public static String Bytes2HexString(byte b[])
{
String ret = "";
for(int i = 0; i < b.length; i++)
{
String hex = Integer.toHexString(b[i] & 0xff);
if(hex.length() == 1)
hex = (new StringBuilder(String.valueOf('0'))).append(hex).toString();
ret = (new StringBuilder(String.valueOf(ret))).append(hex.toUpperCase()).toString();
}
return ret;
}
把之前get请求后面的
0B38EC05B0815AFB59A1B6171DD8378702E08185784ADC47B213462CC176EBC626865CAE40CF998812E25558152958267F28B8BE59532A45283F2A274FA363CB685347955B330164CDEFA8228F011F4BB73C36BFF072DB9C
扔进去解，得到
method=checkUserLoginIFS&idNumber=20142110070202&UserPwd=011211&logonIP=10.0.8.1
到这里可能有人会问，这里的UserPwd=011211与上面json的USER_PASSWORD=?h?g?g+t.[=dR);:不一样，这里是字符串加密后得到的数据。 附上解密代码
public static String Decode(String varCode)
{
String des = new String();
String strKey = new String();
if(varCode == null || varCode.length() == 0)
return "";
strKey = "zxcvbnm,./asdfghjkl;'qwertyuiop[]\1234567890-=` ZXCVBNM<>?:LKJHGFDSAQWERTYUIOP{}|+_)(*&^%$#@!~";
if(varCode.length() % 2 == 1)
varCode = (new StringBuilder(String.valueOf(varCode))).append("?").toString();
des = "";
int n;
for(n = 0; n <= varCode.length() / 2 - 1; n++) { char b = varCode.charAt(n * 2); int a = strKey.indexOf(varCode.charAt(n * 2 + 1)); des = (new StringBuilder(String.valueOf(des))).append((char)(b ^ a)).toString(); System.out.println(des); } n = des.indexOf('01'); if(n > 0)
return des.substring(0, n);
else
return des;
}